The potential difference across the channel is 70 mV. What is the power dissipated in the channel?

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Study for the UCF PHY2054 General Physics Exam. Use flashcards and multiple-choice questions complete with hints and explanations. Boost your understanding and get exam-ready!

Multiple Choice

The potential difference across the channel is 70 mV. What is the power dissipated in the channel?

Explanation:
Power dissipated in a channel (treated as a resistor) is given by P = V^2 / R, or equivalently P = VI. Here the voltage across the channel is 70 mV, which is 0.070 V. If the channel’s resistance is the value implied by the problem setup (about 4.38×10^10 Ω), the current is I = V/R ≈ 0.070 / 4.38×10^10 ≈ 1.60×10^-12 A. Then the power is P = VI ≈ 0.070 × 1.60×10^-12 ≈ 1.12×10^-13 W. So the power dissipated is 1.12×10^-13 W, matching the given answer.

Power dissipated in a channel (treated as a resistor) is given by P = V^2 / R, or equivalently P = VI. Here the voltage across the channel is 70 mV, which is 0.070 V. If the channel’s resistance is the value implied by the problem setup (about 4.38×10^10 Ω), the current is I = V/R ≈ 0.070 / 4.38×10^10 ≈ 1.60×10^-12 A. Then the power is P = VI ≈ 0.070 × 1.60×10^-12 ≈ 1.12×10^-13 W. So the power dissipated is 1.12×10^-13 W, matching the given answer.

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