Electric potential due to a point charge varies with distance as V ∝ 1/r. If the distance from the charge is doubled, how does the potential change?

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Study for the UCF PHY2054 General Physics Exam. Use flashcards and multiple-choice questions complete with hints and explanations. Boost your understanding and get exam-ready!

Multiple Choice

Electric potential due to a point charge varies with distance as V ∝ 1/r. If the distance from the charge is doubled, how does the potential change?

Explanation:
The potential from a point charge scales as V ∝ 1/r, specifically V = kq/r. If you double the distance from the charge, you replace r with 2r, giving V' = kq/(2r) = (1/2)·(kq/r) = V/2. So the potential becomes half as large. The sign follows the charge, but the magnitude is halved. (Note: the electric field falls off faster, as 1/r^2.)

The potential from a point charge scales as V ∝ 1/r, specifically V = kq/r. If you double the distance from the charge, you replace r with 2r, giving V' = kq/(2r) = (1/2)·(kq/r) = V/2. So the potential becomes half as large. The sign follows the charge, but the magnitude is halved. (Note: the electric field falls off faster, as 1/r^2.)

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