A honeybee develops a charge of +14 pC. Approximately how many electrons did the bee lose to acquire this charge?

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Study for the UCF PHY2054 General Physics Exam. Use flashcards and multiple-choice questions complete with hints and explanations. Boost your understanding and get exam-ready!

Multiple Choice

A honeybee develops a charge of +14 pC. Approximately how many electrons did the bee lose to acquire this charge?

Explanation:
Losing electrons creates a positive charge, since each electron carries a negative charge of magnitude e. The number of electrons lost equals the total charge divided by the elementary charge: N = Q/e. Here, Q = 14 pC = 1.4 × 10^-11 C and e ≈ 1.60 × 10^-19 C. So N ≈ (1.4 × 10^-11) / (1.60 × 10^-19) ≈ 8.75 × 10^7. Therefore about 8.7 × 10^7 electrons were lost. The magnitude matches approximately 8.75 × 10^7, so the correct approximate count is around 8.75 × 10^7 electrons.

Losing electrons creates a positive charge, since each electron carries a negative charge of magnitude e. The number of electrons lost equals the total charge divided by the elementary charge: N = Q/e.

Here, Q = 14 pC = 1.4 × 10^-11 C and e ≈ 1.60 × 10^-19 C. So N ≈ (1.4 × 10^-11) / (1.60 × 10^-19) ≈ 8.75 × 10^7.

Therefore about 8.7 × 10^7 electrons were lost. The magnitude matches approximately 8.75 × 10^7, so the correct approximate count is around 8.75 × 10^7 electrons.

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