A 60 W, 240 Ω light bulb filament has a length of 0.60 m. If the potential difference across the filament is 120 V, what is the electric field strength inside the filament?

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Study for the UCF PHY2054 General Physics Exam. Use flashcards and multiple-choice questions complete with hints and explanations. Boost your understanding and get exam-ready!

Multiple Choice

A 60 W, 240 Ω light bulb filament has a length of 0.60 m. If the potential difference across the filament is 120 V, what is the electric field strength inside the filament?

Explanation:
Electric field inside the filament is the potential change per unit length along the filament, E ≈ ΔV/Δs for a uniform drop. Here the potential difference across the filament is 120 V and its length is 0.60 m, so the field is E = 120 V / 0.60 m = 200 V/m. The provided power and resistance numbers also check out (I = V/R = 0.5 A, P = VI = 60 W), confirming consistency.

Electric field inside the filament is the potential change per unit length along the filament, E ≈ ΔV/Δs for a uniform drop. Here the potential difference across the filament is 120 V and its length is 0.60 m, so the field is E = 120 V / 0.60 m = 200 V/m. The provided power and resistance numbers also check out (I = V/R = 0.5 A, P = VI = 60 W), confirming consistency.

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